Some help would be appreciated
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Joined: July 16, 2014
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Some help would be appreciated
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Posted on Mon Aug 04, 2014 9:23 pm
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Confused I am working on a gift for my boyfriend. I am making a dragonback bracelet for him. I started out great, I got about 80% of my project done when I realized I got the wrong sized rings Crying (very sad) I think the AR size of my rings is too small.

can someone please tell me what size rings I need to make a dragonback bracelet? and if possible, where to purchase them?

I was considering purchasing these rings on etsy:

https://www.etsy.com/listing/118265776/100-10mm-black-strong-jumprings-for

but I want to make sure they will work before I purchase/start weaving only to find out that I can't add the last row of rings onto the top of the weave because the rings won't fit together. ugh!!

I'm very new to this (this is my first project) and I've done a bit of research to try and find out for myself but I haven't been able to find a straight answer/solution.

again, some help would be appreciated Very Happy


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Posted on Tue Aug 05, 2014 2:38 am
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Dragonback needs rings with an AR of around 5. The rings you linked to have an AR of 10.
Inner Diameter ÷ Wire Diameter = Aspect Ratio (AR)
10mm ÷ 1mm = 10

Here is a link to how to use the AR pop-up on each weave page. http://www.mailleartisans.org/board/viewtopic.php?t=15495

If you would like to use rings with a wire diameter of 1mm (like the ones you linked to), you need to look for rings with an ID of closer to 5mm instead of 10mm.

If you need more help, keep asking and I'll keep trying to help. Smile


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Posted on Tue Aug 05, 2014 5:01 am
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Of course, that's assuming that the "10mm" is the inner diameter rather than the outer diameter - the listing doesn't actually say.


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Posted on Tue Aug 05, 2014 7:05 am
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If 10mm is the outer diameter, that would make the Aspect Ratio 8.

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Posted on Tue Aug 05, 2014 3:51 pm
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The ID is 9 on these rings (I messaged the seller and asked)

so would that make the AR 9 then?

9 ID ÷ 1mm = AR 9?


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Posted on Tue Aug 05, 2014 6:58 pm
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emilyb93 wrote:
The ID is 9 on these rings (I messaged the seller and asked)

so would that make the AR 9 then?

9 ID ÷ 1mm = AR 9?


Yes. Like Lorraine said, if you intend to use 1mm diameter wire, you will need rings with an ID of about 5mm.


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Joined: July 16, 2014
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Posted on Tue Aug 05, 2014 7:49 pm
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Thanks everyone! Very Happy


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