Calculating Rows and Columns
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Joined: September 11, 2011
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Location: Lexington, Kentucky

Calculating Rows and Columns
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Posted on Sat May 12, 2012 12:03 am
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Not real sure how to word this, but here goes.

If I'm making a 1 square foot section of mail from 18g 3/16 (or any type), how do you figure out how many rows and columns of rings that you'll need? I know that TRL has ring counts per square foot, but I know from experience that if I do a 15x15 ring section, it isn't square. How do I figure out that ratio?

Thanks

Joined: March 27, 2002
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Posted on Sat May 12, 2012 12:33 am
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Hmm. Stretch it out side to side -- row wise -- and it gets squarer.

I never bother with figuring; I just go empirical. Need some more? -- add some more, and done. This is knitting, near enough -- there's such a thing as sweating it too much.

Oh, first post? Welcome and well come!


'The Minstrel Boy to the War is gone...'

Joined: March 3, 2002
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Re: Calculating Rows and Columns
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Posted on Sat May 12, 2012 1:54 am
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Shadowfire19 wrote:
Not real sure how to word this, but here goes.

If I'm making a 1 square foot section of mail from 18g 3/16 (or any type), how do you figure out how many rows and columns of rings that you'll need? I know that TRL has ring counts per square foot, but I know from experience that if I do a 15x15 ring section, it isn't square. How do I figure out that ratio?


no quantity of rings is ever enough.

you'll start thinking, "i'll just make this little patch."
two years from now you'll be giving up one of the rooms in your house to the craft.
ten years from now you'll be hopelessly hooked, wondering what you're going to do with all the things you've made. that are covering every square inch of shelving.


or else.


PSA: remember to stretch.
3.o is fixing everything.

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Posted on Sat May 12, 2012 2:23 am
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if you made a diamond with the 225 links (or however many you would need) it would be the same on all four sides.

Joined: January 29, 2011
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Posted on Sat May 12, 2012 3:57 am
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How about making a 1" or larger patch, and estimating from that sample?

Joined: February 15, 2002
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Posted on Mon May 14, 2012 5:40 pm
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If you're comfortable with math, here's how I figure out rings per square foot on the page http://www.zlosk.com/maille/euro4-1.html. You can also see these equations if you look at the source code.

AR = Aspect ratio
WD = Wire diameter
ID = Ring ID
iph = inches per horizontal ring
ipv = inches per vertical ring

AR = ID/WD
iph = WD * (0.9215*AR - 0.1566)
ipv = WD * (-0.0582*AR^3 + 0.8677*AR^2 - 3.2996*AR + 6.2401)

NumberOfRings = 144/(iph*ipv)

This deals with the weave hanging the "right" way (as in how most armor is made) at half stretch. The equations are based on empirical measurements of several patches of Euro 4-1 at different aspect ratios (range of around 3.1 to 6). iph & ipv are what you need to figure out your rows and columns.


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Joined: September 11, 2011
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Posted on Mon May 14, 2012 10:41 pm
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Easy enough. I did the calculation for 16g 1/4" rings by hand and came up with the same answer as your calculator does, so this works for me. Just curious, but why is there a difference between your formula's count and TRL's count (Granted, it isn't that much)? Is it a rounding difference, a # of decimals difference, or inches vs. millimeters?

So, in looking at your formula, you can figure out how many rows and how many in a row by taking 12/IPV and 12/IPH respectively, right?

Thanks Zlosk and everyone for taking the time to answer.

Joined: February 15, 2002
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Posted on Mon May 14, 2012 10:50 pm
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I imagine the difference lies in our different methodologies, sample sets, and how we defined half-stretch.


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